Math

QuestionFind the intercepts of the equation 3x+6y=18-3x + 6y = -18. What are the x-intercept and y-intercept?

Studdy Solution

STEP 1

Assumptions1. The equation of the line is 3x+6y=18-3x +6y = -18. . We are looking for the x-intercept and y-intercept of this line.

STEP 2

The x-intercept is the point where the line crosses the x-axis. At this point, the y-coordinate is0. So, to find the x-intercept, we set y=0y =0 in the equation of the line and solve for xx.
x+6(0)=18-x +6(0) = -18

STEP 3

implify the equation to solve for xx.
3x=18-3x = -18

STEP 4

Divide both sides of the equation by -3 to solve for xx.
x=183x = \frac{-18}{-3}

STEP 5

Calculate the value of xx.
x=183=x = \frac{-18}{-3} =The x-intercept is.

STEP 6

The y-intercept is the point where the line crosses the y-axis. At this point, the x-coordinate is0. So, to find the y-intercept, we set x=0x =0 in the equation of the line and solve for yy.
3(0)+6y=18-3(0) +6y = -18

STEP 7

implify the equation to solve for yy.
6y=186y = -18

STEP 8

Divide both sides of the equation by6 to solve for yy.
y=186y = \frac{-18}{6}

STEP 9

Calculate the value of yy.
y=186=3y = \frac{-18}{6} = -3The y-intercept is -3.
The intercepts of the line 3x+6y=18-3x +6y = -18 are x-intercept =6 and y-intercept = -3.

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