Math

QuestionFind the vertex of the function f(x)4=(x+1)2f(x) - 4 = (x + 1)^{2}. Choose from: a. (4,1)(-4,1) b. (1,4)(1,-4) c. (1,4)(-1,-4) d. (1,4)(-1,4).

Studdy Solution

STEP 1

Assumptions1. The function is given by f(x)4=(x+1)f(x)-4=(x+1)^{} . The function is in form of a standard quadratic equation y=a(xh)+ky=a(x-h)^+k, where (h,k)(h,k) is the vertex of the parabola.

STEP 2

Rewrite the given function in the form of a standard quadratic equation.
f(x)=(x+1)2+4f(x) = (x+1)^{2} +4

STEP 3

Identify the values of hh and kk in the rewritten function. In the standard form of a quadratic function, hh is the value that is subtracted from xx inside the square, and kk is the constant term.
h=1,k=h = -1, k =

STEP 4

The vertex of the function is given by the point (h,k)(h,k).
Vertex=(1,4)Vertex = (-1,4)So, the vertex of the function f(x)4=(x+1)2f(x)-4=(x+1)^{2} is (1,4)(-1,4).

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