Math  /  Algebra

QuestionFind the values of xx and yy in each equation below:
9. x+yi=29ix+y i=2-9 i
10. 1+10i=(x4)+2yi1+10 i=(x-4)+2 y i

Studdy Solution

STEP 1

What is this asking? We're looking to find the values of x x and y y that make these equations true. Watch out! Don't forget to match the real parts with the real parts and the imaginary parts with the imaginary parts!

STEP 2

1. Match real and imaginary parts for the first equation
2. Solve for x x and y y in the first equation
3. Match real and imaginary parts for the second equation
4. Solve for x x and y y in the second equation

STEP 3

Alrighty! Let's start with the first equation: x+yi=29i x + y i = 2 - 9 i .
The key here is to **match the real parts** and **match the imaginary parts** separately.
So, we have:
- Real part: x=2 x = 2 - Imaginary part: y=9 y = -9

STEP 4

Since we've already matched the parts, we can directly say:
- x=2 x = 2 - y=9 y = -9
And that's it for the first equation!
Easy peasy!

STEP 5

Now, let's tackle the second equation: 1+10i=(x4)+2yi 1 + 10 i = (x - 4) + 2 y i .
Again, we need to **match the real parts** and **match the imaginary parts**.
So, we get:
- Real part: 1=x4 1 = x - 4 - Imaginary part: 10=2y 10 = 2y

STEP 6

Let's solve these equations step by step:
For the real part: \[ 1 = x - 4 $ **Add 4** to both sides to solve for \( x \): \[ x = 5 $
For the imaginary part: \[ 10 = 2y $ **Divide by 2** to solve for \( y \): \[ y = 5 $
And there we have it for the second equation!

STEP 7

For the first equation, the values are x=2 x = 2 and y=9 y = -9 .
For the second equation, the values are x=5 x = 5 and y=5 y = 5 .

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