Math

QuestionFind nn, dd, and pp such that n100=1d=p%\frac{n}{100}=\frac{1}{d}=p \%.

Studdy Solution

STEP 1

Assumptions1. The equation given is n100=1d=p%\frac{n}{100}=\frac{1}{d}=p \%. . We need to find the values of nn, dd, and pp that satisfy this equation.
3. The percentage pp is a decimal value.

STEP 2

First, let's rewrite the equation in a more standard form, separating the equalities.
n100=1d\frac{n}{100}=\frac{1}{d}1d=p%\frac{1}{d}=p \%

STEP 3

Let's solve the first equation for dd.
d=100nd = \frac{100}{n}

STEP 4

Now, let's solve the second equation for dd.
d=1p%d = \frac{1}{p \%}

STEP 5

Since both equations are equal to dd, we can set them equal to each other and solve for nn.
100n=1p%\frac{100}{n} = \frac{1}{p \%}

STEP 6

Cross multiply to solve for nn.
n=100p%n =100 \cdot p \%

STEP 7

Now that we have nn in terms of pp, we can substitute this into the first equation to solve for dd.
d=100100p%d = \frac{100}{100 \cdot p \%}

STEP 8

implify the equation to find dd.
d=1p%d = \frac{1}{p \%}

STEP 9

So, the values of nn, dd, and pp that satisfy the equation aren=100p%n =100 \cdot p \%d=p%d = \frac{}{p \%}p=p%p = p \%

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