Math

QuestionSolve for xx in the equation g(x)=12x+3g(x)=-\frac{1}{2} x+3 where g(x)=1g(x)=-1.

Studdy Solution

STEP 1

Assumptions1. The function is g(x)=1x+3g(x)=-\frac{1}{} x+3 . The value of the function g(x)g(x) is given as 1-1

STEP 2

To find the value of xx that makes g(x)=1g(x) = -1, we set the function equal to 1-1 and solve for xx.
12x+=1-\frac{1}{2} x+ = -1

STEP 3

First, we can isolate the xx term by subtracting 33 from both sides of the equation.
12x=13-\frac{1}{2} x = -1 -3

STEP 4

Calculate the right side of the equation.
12x=4-\frac{1}{2} x = -4

STEP 5

To solve for xx, we can multiply both sides of the equation by 2-2 to get rid of the negative fraction.
x=4×2x = -4 \times -2

STEP 6

Calculate the value of xx.
x=8x =8So, the value of xx that makes g(x)=1g(x) = -1 is x=8x =8.

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