Math

Question Find the value of xx in the simplified expression gx+h3=1g6+1h3g^{x} + h^{-3} = \frac{1}{g^{6}} + \frac{1}{h^{3}}.

Studdy Solution

STEP 1

Assumptions
1. The expressions are given as gx+h3=1g6+1h3g^{x}+h^{-3}=\frac{1}{g^{6}}+\frac{1}{h^{3}}.
2. We need to find the value of xx.
3. The properties of exponents will be used to solve for xx.

STEP 2

Recognize that h3h^{-3} is the same as 1h3\frac{1}{h^{3}} by the definition of negative exponents.
h3=1h3h^{-3} = \frac{1}{h^{3}}

STEP 3

Since we have a term 1g6\frac{1}{g^{6}} on the right side of the equation, we can rewrite gxg^{x} in terms of a fraction with a negative exponent if it equals 1g6\frac{1}{g^{6}}.
gx=1g6    gx=g6g^{x} = \frac{1}{g^{6}} \implies g^{x} = g^{-6}

STEP 4

Now that we have gx=g6g^{x} = g^{-6}, we can equate the exponents since the bases are the same and non-zero.
x=6x = -6
The value of xx is 6-6.

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