Math

QuestionFind the value of the function f(x)=x210xf(x)=-x^{2}-10 x at x=2x=-2. What is f(2)f(-2)?

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=x10xf(x)=-x^{}-10x . We need to find the value of the function at x=x=-

STEP 2

To find the value of the function at x=2x=-2, we need to substitute x=2x=-2 into the function.
f(2)=(2)210(2)f(-2) = -(-2)^{2}-10(-2)

STEP 3

First, calculate the value of (2)2(-2)^{2}.
(2)2=(-2)^{2} =So, the function becomesf(2)=10(2)f(-2) = - -10(-2)

STEP 4

Next, calculate the value of 10(2)10(-2).
10(2)=2010(-2) = -20So, the function becomesf(2)=4(20)f(-2) = -4 - (-20)

STEP 5

Subtracting a negative number is the same as adding the positive of that number. So, the function becomesf(2)=4+20f(-2) = -4 +20

STEP 6

Finally, calculate the value of 4+20-4 +20.
f(2)=4+20=16f(-2) = -4 +20 =16So, f(2)=16f(-2) =16.

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