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QuestionFind the value of h(−2)h(-2) for the function h(x)=4x2+5h(x)=4 x^{2}+5.

Studdy Solution

STEP 1

Assumptions1. The function f(x)=4x+3f(x)=4x+3 is given. . The function g(x)=x+4x+5g(x)=x^{}+4x+5 is given.
3. The function h(x)=4x+5h(x)=4x^{}+5 is given.
4. We are asked to find the value of h(−)h(-).

STEP 2

To find the value of h(−2)h(-2), we need to substitute x=−2x=-2 into the function h(x)h(x).
h(−2)=4(−2)2+5h(-2) =4(-2)^{2}+5

STEP 3

Calculate the square of −2-2.
(−2)2=(-2)^{2} =

STEP 4

Substitute (−2)2(-2)^{2} with 44 in the equation.
h(−2)=4(4)+h(-2) =4(4)+

STEP 5

Calculate the multiplication.
h(−2)=16+5h(-2) =16+5

STEP 6

Calculate the addition.
h(−2)=21h(-2) =21So, h(−2)=21h(-2) =21.

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