Math

QuestionCalculate (4(2)+(1))÷3(31)÷((2)(1))(4(-2)+(-1)) \div 3 - (3 \cdot 1) \div((-2)(-1)) for a=2,b=3,c=1,d=1a=-2, b=3, c=-1, d=1.

Studdy Solution

STEP 1

Assumptions1. The values of the variables are as follows a=a=-, b=3b=3, c=1c=-1, and d=1d=1. . The operations in the expression are carried out from left to right.

STEP 2

First, we need to substitute the given values of aa, bb, cc, and dd into the expression.
(4a+c)÷b(bd)÷(ac)(4 a+c) \div b-(b d) \div(a c)(4(2)+(1))÷(×1)÷((2)×(1))(4(-2)+(-1)) \div-( \times1) \div((-2) \times (-1))

STEP 3

Now, calculate the values inside the brackets.
(81)÷3(3)÷2(-8-1) \div3-(3) \div2

STEP 4

Calculate the division operations.
9÷33÷2-9 \div3-3 \div2

STEP 5

Calculate the results of the division operations.
31.5-3-1.5

STEP 6

Finally, subtract the second value from the first to find the value of the expression.
31.5=4.5-3-1.5 = -4.5So, the value of the expression when a=2a=-2, b=3b=3, c=1c=-1, and d=1d=1 is 4.5-4.5 or 412-4 \frac{1}{2}.
The correct answer is (c) 412-4 \frac{1}{2}.

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