QuestionFind the value of $C$ in the probability distribution where $p(0)=0.1$ , $p(1)=0.3$ , $p(2)=C$ , $p(3)=0.2$ .

Studdy Solution

STEP 1

Assumptions1. The given values are probabilities of a discrete probability distribution. . The sum of all probabilities in a probability distribution is1.

STEP 2

First, we need to find the sum of the given probabilities.
$Sum\, of\, given\, probabilities = p(x=0) + p(x=1) + p(x=)$

STEP 3

Now, plug in the given values for the probabilities to calculate the sum.
$Sum\, of\, given\, probabilities =0.1 +0.3 +0.2$

STEP 4

Calculate the sum of the given probabilities.
$Sum\, of\, given\, probabilities =0.1 +0.3 +0.2 =0.6$

STEP 5

Now that we have the sum of the given probabilities, we can find the missing probability. This can be done by subtracting the sum of the given probabilities from1.
$Missing\, probability =1 - Sum\, of\, given\, probabilities$

STEP 6

Plug in the value for the sum of the given probabilities to calculate the missing probability.
$Missing\, probability =1 -0.6$

STEP 7

Calculate the missing probability.
$Missing\, probability =1 -0.6 =0.4$ The missing probability for $x=2$ is0.4.

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QuestionFind the value of $C$ in the probability distribution where $p(0)=0.1$ , $p(1)=0.3$ , $p(2)=C$ , $p(3)=0.2$ .

Studdy Solution

STEP 1

Assumptions1. The given values are probabilities of a discrete probability distribution. . The sum of all probabilities in a probability distribution is1.

STEP 2

First, we need to find the sum of the given probabilities.
$Sum\, of\, given\, probabilities = p(x=0) + p(x=1) + p(x=)$

STEP 3

Now, plug in the given values for the probabilities to calculate the sum.
$Sum\, of\, given\, probabilities =0.1 +0.3 +0.2$

STEP 4

Calculate the sum of the given probabilities.
$Sum\, of\, given\, probabilities =0.1 +0.3 +0.2 =0.6$

STEP 5

Now that we have the sum of the given probabilities, we can find the missing probability. This can be done by subtracting the sum of the given probabilities from1.
$Missing\, probability =1 - Sum\, of\, given\, probabilities$

STEP 6

Plug in the value for the sum of the given probabilities to calculate the missing probability.
$Missing\, probability =1 -0.6$

STEP 7

Calculate the missing probability.
$Missing\, probability =1 -0.6 =0.4$ The missing probability for $x=2$ is0.4.

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QuestionFind the value of CCC in the probability distribution where p(0)=0.1p(0)=0.1p(0)=0.1, p(1)=0.3p(1)=0.3p(1)=0.3, p(2)=Cp(2)=Cp(2)=C, p(3)=0.2p(3)=0.2p(3)=0.2.

Studdy Solution

STEP 1

Assumptions1. The given values are probabilities of a discrete probability distribution. . The sum of all probabilities in a probability distribution is1.

STEP 2

First, we need to find the sum of the given probabilities.Sum of given probabilities=p(x=0)+p(x=1)+p(x=)Sum\, of\, given\, probabilities = p(x=0) + p(x=1) + p(x=)Sumofgivenprobabilities=p(x=0)+p(x=1)+p(x=)

STEP 3

Now, plug in the given values for the probabilities to calculate the sum.Sum of given probabilities=0.1+0.3+0.2Sum\, of\, given\, probabilities =0.1 +0.3 +0.2Sumofgivenprobabilities=0.1+0.3+0.2

STEP 4

Calculate the sum of the given probabilities.Sum of given probabilities=0.1+0.3+0.2=0.6Sum\, of\, given\, probabilities =0.1 +0.3 +0.2 =0.6Sumofgivenprobabilities=0.1+0.3+0.2=0.6

STEP 5

STEP 6

Plug in the value for the sum of the given probabilities to calculate the missing probability.Missing probability=1−0.6Missing\, probability =1 -0.6Missingprobability=1−0.6

STEP 7

Calculate the missing probability.Missing probability=1−0.6=0.4Missing\, probability =1 -0.6 =0.4Missingprobability=1−0.6=0.4The missing probability for x=2x=2x=2 is0.4.

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QuestionFind the value of $C$ in the probability distribution where $p(0)=0.1$ , $p(1)=0.3$ , $p(2)=C$ , $p(3)=0.2$ .

First, we need to find the sum of the given probabilities.
$Sum\, of\, given\, probabilities = p(x=0) + p(x=1) + p(x=)$

Now, plug in the given values for the probabilities to calculate the sum.
$Sum\, of\, given\, probabilities =0.1 +0.3 +0.2$

Calculate the sum of the given probabilities.
$Sum\, of\, given\, probabilities =0.1 +0.3 +0.2 =0.6$

Plug in the value for the sum of the given probabilities to calculate the missing probability.
$Missing\, probability =1 -0.6$

Calculate the missing probability.
$Missing\, probability =1 -0.6 =0.4$ The missing probability for $x=2$ is0.4.