Math

Question Find solutions to the quadratic equation 2n(3n12)=02n(3n-12)=0.

Studdy Solution

STEP 1

Assumptions
1. We are given the equation 2n(3n12)=02n(3n - 12) = 0.
2. We need to find the values of nn that satisfy this equation.

STEP 2

To solve the equation, we will use the zero product property, which states that if the product of two numbers is zero, then at least one of the factors must be zero.
2n(3n12)=02n(3n - 12) = 0

STEP 3

Set each factor equal to zero and solve for nn.
First factor: 2n=02n = 0
Second factor: (3n12)=0(3n - 12) = 0

STEP 4

Solve the first equation for nn.
2n=02n = 0
Divide both sides by 2:
2n2=02\frac{2n}{2} = \frac{0}{2}

STEP 5

Calculate the value of nn from the first equation.
n=0n = 0

STEP 6

Solve the second equation for nn.
3n12=03n - 12 = 0
Add 12 to both sides:
3n=123n = 12

STEP 7

Divide both sides by 3 to find the value of nn.
3n3=123\frac{3n}{3} = \frac{12}{3}

STEP 8

Calculate the value of nn from the second equation.
n=4n = 4

STEP 9

List the solutions for nn from both equations.
The solutions are n=0n = 0 and n=4n = 4.
Therefore, the correct answer is A. 0 and 4.

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