QuestionSolve $2(x+z)-y$ for $x=6$ , $y=8$ , and $z=3$ . What is the result?

Studdy Solution

STEP 1

Assumptions1. The equation is $(x+z)-y$ . The value of $x$ is63. The value of $y$ is84. The value of $z$ is3

STEP 2

We can start solving the equation by substituting the given values of $x$ , $y$ , and $z$ into the equation.
$2(x+z)-y =2(6+)-8$

STEP 3

First, perform the addition inside the parentheses.
$2(6+3)-8 =2(9)-8$

STEP 4

Next, perform the multiplication.
$2(9)-8 =18-8$

STEP 5

Finally, perform the subtraction to find the solution.
$18-8 =10$ So, the solution to the equation $2(x+z)-y$ with $x=$ , $y=8$ , and $z=3$ is10.

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QuestionSolve $2(x+z)-y$ for $x=6$ , $y=8$ , and $z=3$ . What is the result?

Studdy Solution

STEP 1

Assumptions1. The equation is $(x+z)-y$ . The value of $x$ is63. The value of $y$ is84. The value of $z$ is3

STEP 2

We can start solving the equation by substituting the given values of $x$ , $y$ , and $z$ into the equation.
$2(x+z)-y =2(6+)-8$

STEP 3

First, perform the addition inside the parentheses.
$2(6+3)-8 =2(9)-8$

STEP 4

Next, perform the multiplication.
$2(9)-8 =18-8$

STEP 5

Finally, perform the subtraction to find the solution.
$18-8 =10$ So, the solution to the equation $2(x+z)-y$ with $x=$ , $y=8$ , and $z=3$ is10.

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QuestionSolve 2(x+z)−y2(x+z)-y2(x+z)−y for x=6x=6x=6, y=8y=8y=8, and z=3z=3z=3. What is the result?

Studdy Solution

STEP 1

Assumptions1. The equation is (x+z)−y(x+z)-y(x+z)−y . The value of xxx is63. The value of yyy is84. The value of zzz is3

STEP 2

We can start solving the equation by substituting the given values of xxx, yyy, and zzz into the equation.2(x+z)−y=2(6+)−82(x+z)-y =2(6+)-82(x+z)−y=2(6+)−8

STEP 3

First, perform the addition inside the parentheses.2(6+3)−8=2(9)−82(6+3)-8 =2(9)-82(6+3)−8=2(9)−8

STEP 4

Next, perform the multiplication.2(9)−8=18−82(9)-8 =18-82(9)−8=18−8

STEP 5

Finally, perform the subtraction to find the solution.18−8=1018-8 =1018−8=10So, the solution to the equation 2(x+z)−y2(x+z)-y2(x+z)−y with x=x=x=, y=8y=8y=8, and z=3z=3z=3 is10.

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QuestionSolve $2(x+z)-y$ for $x=6$ , $y=8$ , and $z=3$ . What is the result?

Assumptions1. The equation is $(x+z)-y$ . The value of $x$ is63. The value of $y$ is84. The value of $z$ is3

We can start solving the equation by substituting the given values of $x$ , $y$ , and $z$ into the equation.
$2(x+z)-y =2(6+)-8$

First, perform the addition inside the parentheses.
$2(6+3)-8 =2(9)-8$

Next, perform the multiplication.
$2(9)-8 =18-8$

Finally, perform the subtraction to find the solution.
$18-8 =10$ So, the solution to the equation $2(x+z)-y$ with $x=$ , $y=8$ , and $z=3$ is10.