Math  /  Algebra

QuestionFind the slope and yy-intercept of the line. 2x3y=6-2 x-3 y=-6

Studdy Solution

STEP 1

What is this asking? We're looking for the slope and *y*-intercept of a line given its equation in *standard form*! Watch out! Don't mix up the *x* and *y* intercepts!
Also, remember the slope is the number multiplying *x* when the equation is in *slope-intercept form*.

STEP 2

1. Rewrite the equation
2. Identify slope and *y*-intercept

STEP 3

We want to rewrite the equation in *slope-intercept form*, which is y=mx+by = mx + b, where mm is the **slope** and bb is the **y-intercept**.
To do this, we first isolate the *y* term.
Let's add 2x2x to both sides of the equation 2x3y=6-2x - 3y = -6: 2x3y+2x=6+2x-2x - 3y + 2x = -6 + 2x 3y=2x6-3y = 2x - 6

STEP 4

Now, we divide both sides by 3-3 to get *y* by itself: 3y3=2x63\frac{-3y}{-3} = \frac{2x - 6}{-3} y=2x3+63y = \frac{2x}{-3} + \frac{-6}{-3}y=23x+2y = -\frac{2}{3}x + 2Now our equation is in *slope-intercept form*!

STEP 5

Remember, the *slope-intercept form* is y=mx+by = mx + b, where mm is the **slope**.
Looking at our equation y=23x+2y = -\frac{2}{3}x + 2, we can see that the **slope** mm is 23-\frac{2}{3}.

STEP 6

In the *slope-intercept form* y=mx+by = mx + b, bb represents the **y-intercept**.
In our equation y=23x+2y = -\frac{2}{3}x + 2, the **y-intercept** is 22.
This means the line crosses the *y*-axis at the point (0,2)(0, 2).

STEP 7

The **slope** of the line is 23-\frac{2}{3} and the **y-intercept** is 22.

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