QuestionCalculate the product: $\left(\frac{-8}{9}\right)\left(\frac{-7}{22}\right)=\square$ (Enter an integer or simplified fraction.)

Studdy Solution

STEP 1

Assumptions1. We are multiplying two fractions. . The fractions are $\frac{-8}{9}$ and $\frac{-7}{22}$ .

STEP 2

To multiply two fractions, we multiply the numerators (the top numbers) together and the denominators (the bottom numbers) together.
$\left(\frac{-8}{9}\right)\left(\frac{-7}{22}\right) = \frac{-8 \times -7}{9 \times22}$

STEP 3

Now, we can calculate the product of the numerators and the product of the denominators.
$\frac{-8 \times -7}{9 \times22} = \frac{56}{198}$

STEP 4

The fraction $\frac{56}{198}$ can be simplified by dividing both the numerator and the denominator by their greatest common divisor (GCD). The GCD of56 and198 is2.
$\frac{56}{198} = \frac{56 \div2}{198 \div2} = \frac{28}{99}$ So, the product of $\left(\frac{-8}{9}\right)\left(\frac{-7}{22}\right)$ is $\frac{28}{99}$ .

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