Math

QuestionCalculate the windchill temperature difference at 10F10^{\circ} \mathrm{F} for wind speeds of 5 mph and 25 mph.

Studdy Solution

STEP 1

Assumptions1. We are using the windchill temperature index chart provided by the National Weather Service. . The actual air temperature is 1010^{\circ} \mathrm{}.
3. We are comparing the perceived temperatures at wind speeds of5 miles per hour and25 miles per hour.

STEP 2

First, we need to find the perceived temperature at a wind speed of5 miles per hour. According to the windchill temperature index chart, when the actual temperature is 1010^{\circ} \mathrm{} and the wind speed is5 miles per hour, the perceived temperature is 66^{\circ} \mathrm{}.
Perceivedtemperatureat5mph=6Perceived\, temperature\, at\,5\, mph =6^{\circ} \mathrm{}

STEP 3

Next, we need to find the perceived temperature at a wind speed of25 miles per hour. According to the windchill temperature index chart, when the actual temperature is 1010^{\circ} \mathrm{} and the wind speed is25 miles per hour, the perceived temperature is 9-9^{\circ} \mathrm{}.
Perceivedtemperatureat25mph=9Perceived\, temperature\, at\,25\, mph = -9^{\circ} \mathrm{}

STEP 4

Now that we have the perceived temperatures at both wind speeds, we can find the difference in perceived temperature by subtracting the perceived temperature at25 miles per hour from the perceived temperature at miles per hour.
Differenceinperceivedtemperature=PerceivedtemperatureatmphPerceivedtemperatureat25mphDifference\, in\, perceived\, temperature = Perceived\, temperature\, at\,\, mph - Perceived\, temperature\, at\,25\, mph

STEP 5

Plug in the values for the perceived temperatures at5 miles per hour and25 miles per hour to calculate the difference in perceived temperature.
Differenceinperceivedtemperature=(9)Difference\, in\, perceived\, temperature =^{\circ} \mathrm{} - (-9^{\circ} \mathrm{})

STEP 6

Calculate the difference in perceived temperature.
Differenceinperceivedtemperature=6(9)=15Difference\, in\, perceived\, temperature =6^{\circ} \mathrm{} - (-9^{\circ} \mathrm{}) =15^{\circ} \mathrm{}The difference in perceived temperature when the wind speed is5 miles per hour and25 miles per hour, given that the actual air temperature is 1010^{\circ} \mathrm{}, is 1515^{\circ} \mathrm{}.

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