QuestionFind the number of protons $(p)$ and electrons $(e)$ in $\mathrm{Mg}^{2+}$ . A) $10 p, 12 e$ B) $12 p, 12 e$ C) $12 p, 10 e$ D) $12 p, 14 e$ E) $10 p, 10 e$

Studdy Solution

STEP 1

Assumptions1. The given is a magnesium ion $\mathrm{Mg}^{+}$ . . The number of protons in an atom is equal to its atomic number.
3. The number of electrons in an ion is equal to the number of protons minus the charge of the ion (if the ion is positive, as it is in this case).

STEP 2

First, we need to find the atomic number of magnesium. The atomic number of magnesium is12. This means that a neutral magnesium atom has12 protons.
$p = Atomic\, number\, of\, Mg =12$

STEP 3

Next, we need to find the number of electrons in the $\mathrm{Mg}^{2+}$ ion. The charge of the ion is +2, which means that it has lost2 electrons.
$e = p - Charge\, of\, the\, ion$

STEP 4

Plug in the values for the number of protons and the charge of the ion to calculate the number of electrons.
$e =12 -2$

STEP 5

Calculate the number of electrons.
$e =12 -2 =10$ The $\mathrm{Mg}^{2+}$ ion has12 protons and10 electrons, so the correct answer is option C) $12 p,10 e$ .

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QuestionFind the number of protons $(p)$ and electrons $(e)$ in $\mathrm{Mg}^{2+}$ . A) $10 p, 12 e$ B) $12 p, 12 e$ C) $12 p, 10 e$ D) $12 p, 14 e$ E) $10 p, 10 e$

Studdy Solution

STEP 1

Assumptions1. The given is a magnesium ion $\mathrm{Mg}^{+}$ . . The number of protons in an atom is equal to its atomic number.
3. The number of electrons in an ion is equal to the number of protons minus the charge of the ion (if the ion is positive, as it is in this case).

STEP 2

First, we need to find the atomic number of magnesium. The atomic number of magnesium is12. This means that a neutral magnesium atom has12 protons.
$p = Atomic\, number\, of\, Mg =12$

STEP 3

Next, we need to find the number of electrons in the $\mathrm{Mg}^{2+}$ ion. The charge of the ion is +2, which means that it has lost2 electrons.
$e = p - Charge\, of\, the\, ion$

STEP 4

Plug in the values for the number of protons and the charge of the ion to calculate the number of electrons.
$e =12 -2$

STEP 5

Calculate the number of electrons.
$e =12 -2 =10$ The $\mathrm{Mg}^{2+}$ ion has12 protons and10 electrons, so the correct answer is option C) $12 p,10 e$ .

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QuestionFind the number of protons (p)(p)(p) and electrons (e)(e)(e) in Mg2+\mathrm{Mg}^{2+}Mg2+. A) 10p,12e10 p, 12 e10p,12e B) 12p,12e12 p, 12 e12p,12e C) 12p,10e12 p, 10 e12p,10e D) 12p,14e12 p, 14 e12p,14e E) 10p,10e10 p, 10 e10p,10e

Studdy Solution

STEP 1

Assumptions1. The given is a magnesium ion Mg+\mathrm{Mg}^{+}Mg+. . The number of protons in an atom is equal to its atomic number.3. The number of electrons in an ion is equal to the number of protons minus the charge of the ion (if the ion is positive, as it is in this case).

STEP 2

First, we need to find the atomic number of magnesium. The atomic number of magnesium is12. This means that a neutral magnesium atom has12 protons.p=Atomic number of Mg=12p = Atomic\, number\, of\, Mg =12p=AtomicnumberofMg=12

STEP 3

Next, we need to find the number of electrons in the Mg2+\mathrm{Mg}^{2+}Mg2+ ion. The charge of the ion is +2, which means that it has lost2 electrons.e=p−Charge of the ione = p - Charge\, of\, the\, ione=p−Chargeoftheion

STEP 4

Plug in the values for the number of protons and the charge of the ion to calculate the number of electrons.e=12−2e =12 -2e=12−2

STEP 5

Calculate the number of electrons.e=12−2=10e =12 -2 =10e=12−2=10The Mg2+\mathrm{Mg}^{2+}Mg2+ ion has12 protons and10 electrons, so the correct answer is option C) 12p,10e12 p,10 e12p,10e.

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QuestionFind the number of protons $(p)$ and electrons $(e)$ in $\mathrm{Mg}^{2+}$ . A) $10 p, 12 e$ B) $12 p, 12 e$ C) $12 p, 10 e$ D) $12 p, 14 e$ E) $10 p, 10 e$

Assumptions1. The given is a magnesium ion $\mathrm{Mg}^{+}$ . . The number of protons in an atom is equal to its atomic number.
3. The number of electrons in an ion is equal to the number of protons minus the charge of the ion (if the ion is positive, as it is in this case).

First, we need to find the atomic number of magnesium. The atomic number of magnesium is12. This means that a neutral magnesium atom has12 protons.
$p = Atomic\, number\, of\, Mg =12$

Next, we need to find the number of electrons in the $\mathrm{Mg}^{2+}$ ion. The charge of the ion is +2, which means that it has lost2 electrons.
$e = p - Charge\, of\, the\, ion$

Plug in the values for the number of protons and the charge of the ion to calculate the number of electrons.
$e =12 -2$

Calculate the number of electrons.
$e =12 -2 =10$ The $\mathrm{Mg}^{2+}$ ion has12 protons and10 electrons, so the correct answer is option C) $12 p,10 e$ .