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Math

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PROBLEM

Find the next four terms of the sequence ana_n given the values: 16, 25, 36, 49, 64.

STEP 1

Assumptions1. The sequence is {an}\{a_{n}\} with known values a0,a1,a,a3,a4a_{0}, a_{1}, a_{}, a_{3}, a_{4} which are16,25,36,49,64 respectively.
. The sequence follows a certain pattern which we need to determine.

STEP 2

We observe the given sequence to identify a pattern.a0=16,a1=25,a2=36,a=49,a4=64a_{0} =16, a_{1} =25, a_{2} =36, a_{} =49, a_{4} =64

STEP 3

We notice that each number in the sequence is a perfect square.a0=2,a1=52,a2=62,a3=72,a=82a_{0} =^2, a_{1} =5^2, a_{2} =6^2, a_{3} =7^2, a_{} =8^2

STEP 4

We can see that the base of the square for each term in the sequence is increasing by1 for each subsequent term.an=(n+4)2a_{n} = (n+4)^2

STEP 5

We can now use this pattern to calculate the next four terms in the sequence.a5=(5+4)2,a=(+4)2,a7=(7+4)2,a8=(8+4)2a_{5} = (5+4)^2, a_{} = (+4)^2, a_{7} = (7+4)^2, a_{8} = (8+4)^2

SOLUTION

Calculate the values of a5,a6,a,a8a_{5}, a_{6}, a_{}, a_{8}.
a5=92=81,a6=102=100,a=112=121,a8=122=144a_{5} =9^2 =81, a_{6} =10^2 =100, a_{} =11^2 =121, a_{8} =12^2 =144The next four values of the sequence {an}\{a_{n}\} are81,100,121,144.

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