QuestionFind moles of Al, S, and O in 3.00 moles of $\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}$ and list as numbers: Al, S, O.

Studdy Solution

STEP 1

Assumptions1. The given compound is aluminum sulfate, $\mathrm{Al}_{}\left(\mathrm{}_{4}\right)_{3}$ . We have3.00 moles of aluminum sulfate3. The atomic composition of aluminum sulfate is atoms of aluminum (Al),3 atoms of sulfur (), and12 atoms of oxygen () per formula unit

STEP 2

First, we need to calculate the number of moles of aluminum. Since there are2 moles of aluminum in one mole of aluminum sulfate, we multiply the number of moles of aluminum sulfate by2.
$\text{Moles of Al} = \text{Moles of Al}_{2}\left(\mathrm{}_{4}\right)_{} \times2$

STEP 3

Now, plug in the given value for the moles of aluminum sulfate to calculate the moles of aluminum.
$\text{Moles of Al} =3.00 \times2$

STEP 4

Calculate the number of moles of aluminum.
$\text{Moles of Al} =3.00 \times2 =6.00$

STEP 5

Next, we calculate the number of moles of sulfur. Since there are3 moles of sulfur in one mole of aluminum sulfate, we multiply the number of moles of aluminum sulfate by3.
$\text{Moles of} = \text{Moles of Al}_{2}\left(\mathrm{}_{4}\right)_{3} \times3$

STEP 6

Now, plug in the given value for the moles of aluminum sulfate to calculate the moles of sulfur.
$\text{Moles of} =3.00 \times3$

STEP 7

Calculate the number of moles of sulfur.
$\text{Moles of} =3.00 \times3 =9.00$

STEP 8

Finally, we calculate the number of moles of oxygen. Since there are12 moles of oxygen in one mole of aluminum sulfate, we multiply the number of moles of aluminum sulfate by12.
$\text{Moles of O} = \text{Moles of Al}_{2}\left(\mathrm{}_{4}\right)_{3} \times12$

STEP 9

Now, plug in the given value for the moles of aluminum sulfate to calculate the moles of oxygen.
$\text{Moles of O} =3.00 \times12$

STEP 10

Calculate the number of moles of oxygen.
$\text{Moles of O} =3.00 \times12 =36.00$ The number of moles of $\mathrm{Al}, \mathrm{}$ , and $\mathrm{}$ atoms are6.00,9.00, and36.00, respectively.

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