Math  /  Algebra

Question㮁 Find the missing number so that the equation has infinitely many solutions. 2x47x=x42 x-4-7 x=\square x-4 Submit

Studdy Solution

STEP 1

1. The equation is 2x47x=x42x - 4 - 7x = \square x - 4.
2. For the equation to have infinitely many solutions, both sides of the equation must be identical after simplification.

STEP 2

1. Simplify the left side of the equation.
2. Set the simplified left side equal to the right side.
3. Determine the value of the missing number (\square) that makes both sides identical.

STEP 3

Simplify the left side of the equation:
2x47x 2x - 4 - 7x
Combine like terms:
(2x7x)4=5x4 (2x - 7x) - 4 = -5x - 4

STEP 4

Set the simplified left side equal to the right side of the equation:
5x4=x4 -5x - 4 = \square x - 4

STEP 5

For the equation to have infinitely many solutions, the coefficients of xx and the constant terms on both sides must be equal. This means:
5x=x -5x = \square x
Thus, the missing number must be:
=5 \square = -5
The missing number is 5\boxed{-5}.

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