Math

QuestionFind the inverse of f(x)=x5f(x)=\sqrt{x-5} for x5x \geq 5.

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=x5f(x)=\sqrt{x-5} . The domain of the function is [5,)[5, \infty)3. We need to find the inverse of the function

STEP 2

The first step in finding the inverse of a function is to replace the function notation f(x)f(x) with yy.
y=x5y = \sqrt{x-5}

STEP 3

Next, we switch the roles of xx and yy. This means we replace every xx in our equation with yy and every yy with xx.
x=y5x = \sqrt{y-5}

STEP 4

Now, we need to solve this equation for yy to get the inverse function. First, we square both sides of the equation to eliminate the square root.
(x)2=(y)2(x)^2 = (\sqrt{y-})^2

STEP 5

implify the equation.
x2=y5x^2 = y-5

STEP 6

Add5 to both sides of the equation to isolate yy.
x2+5=yx^2 +5 = y

STEP 7

Now we have the inverse function. However, we need to consider the domain of the original function. The original function has a domain of [5,)[5, \infty), which means the range of the inverse function is [5,)[5, \infty). Therefore, we need to restrict the domain of the inverse function to [0,)[0, \infty) to match the range of the original function.
The inverse function is f1(x)=x2+5f^{-1}(x) = x^2 +5 for x0x \geq0.

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