Math

QuestionFind the inverse function f1(x)f^{-1}(x) for f(x)=2x+16f(x) = 2x + 16. What is f1(x)f^{-1}(x)?

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=x+16f(x)=x+16 . We are asked to find the inverse of the function, denoted as f1(x)f^{-1}(x)

STEP 2

The inverse of a function f(x)f(x) is found by swapping xx and yy and solving for yy. So, we start by writing the function f(x)f(x) as y=2x+16y=2x+16.

STEP 3

Swap xx and yy in the equation.
x=2y+16x=2y+16

STEP 4

Now, we solve for yy to find the inverse function. First, subtract16 from both sides of the equation.
x16=2yx-16=2y

STEP 5

Next, divide both sides of the equation by2 to isolate yy.
y=x162y=\frac{x-16}{2}

STEP 6

Finally, we replace yy with f1(x)f^{-1}(x) to denote that we have found the inverse function.
f1(x)=x162f^{-1}(x)=\frac{x-16}{2}So, the inverse of the function f(x)=2x+16f(x)=2x+16 is f1(x)=x162f^{-1}(x)=\frac{x-16}{2}.

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