Math

QuestionFind the integral 1x28x+65dx\int \frac{1}{x^{2}-8 x+65} d x. Choose the correct answer: (A), (B), (C), or (D).

Studdy Solution

STEP 1

Assumptions1. We are asked to find the integral of the function 1x8x+65\frac{1}{x^{}-8 x+65}. . The integral is indefinite, so we will have a constant of integration in our final answer.

STEP 2

The given function can be rewritten as 1(x4)2+49\frac{1}{(x-4)^{2}+49}, which is in the form of 1a2+x2\frac{1}{a^{2}+x^{2}}. The integral of this form is 1aarctan(xa)+C\frac{1}{a}\arctan\left(\frac{x}{a}\right)+C.

STEP 3

Rewrite the function in the form of 1a2+x2\frac{1}{a^{2}+x^{2}}.
1x28x+65dx=1(x)2+49dx\int \frac{1}{x^{2}-8 x+65} d x = \int \frac{1}{(x-)^{2}+49} dx

STEP 4

Now, we can see that the function is in the form 1a2+x2\frac{1}{a^{2}+x^{2}} where a=7a=7 and x=x4x=x-4.

STEP 5

Substitute the values of aa and xx into the formula 1aarctan(xa)+C\frac{1}{a}\arctan\left(\frac{x}{a}\right)+C.
1(x4)2+49dx=17arctan(x47)+C\int \frac{1}{(x-4)^{2}+49} dx = \frac{1}{7}\arctan\left(\frac{x-4}{7}\right)+CSo, the integral of the given function is 17arctan(x47)+C\frac{1}{7}\arctan\left(\frac{x-4}{7}\right)+C.
This corresponds to answer choice ().

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