Math  /  Calculus

QuestionFind the integral given below. Check your answer by differentiation. 6x5x6+1dx=\int \frac{6 x^{5}}{x^{6}+1} d x= \square +C+C

Studdy Solution

STEP 1

What is this asking? We need to find the integral of a fraction with xx and then double-check our work by taking the derivative of our answer. Watch out! Don't forget the +C+C when integrating and remember the chain rule when differentiating!

STEP 2

1. Set up the substitution
2. Compute the integral
3. Check the result

STEP 3

Let's **define** u=x6+1u = x^6 + 1.
This will help us simplify the integral.
We're picking this *specific* uu because we see an x6x^6 in the numerator, which is *very close* to the derivative of the denominator x6+1x^6 + 1.

STEP 4

Now, let's **find** the derivative of uu with respect to xx.
We get dudx=6x5.\frac{du}{dx} = 6x^5.

STEP 5

Next, we **solve** for dxdx.
We get dx=du6x5.dx = \frac{du}{6x^5}. This helps us rewrite the integral in terms of uu.

STEP 6

Let's **rewrite** the original integral using our substitution: 6x5x6+1dx=6x5udu6x5.\int \frac{6x^5}{x^6 + 1} dx = \int \frac{6x^5}{u} \cdot \frac{du}{6x^5}.

STEP 7

Now, we can **simplify** the integral by dividing to one.
Notice that the 6x56x^5 terms divide to one, leaving us with 1udu.\int \frac{1}{u} du. Much nicer, right?!

STEP 8

We know that the integral of 1u\frac{1}{u} is lnu\ln|u|.
So, we have 1udu=lnu+C.\int \frac{1}{u} du = \ln|u| + C.

STEP 9

Finally, let's **substitute** back x6+1x^6 + 1 for uu to get our **answer** in terms of xx: lnx6+1+C.\ln|x^6 + 1| + C. Since x6x^6 is always non-negative and we add 11 to it, x6+1x^6 + 1 is always positive.
Therefore, we can remove the absolute value: ln(x6+1)+C.\ln(x^6 + 1) + C.

STEP 10

To **check our work**, let's differentiate our answer ln(x6+1)+C\ln(x^6 + 1) + C using the chain rule.

STEP 11

The **derivative** of ln(x6+1)\ln(x^6 + 1) is 1x6+1\frac{1}{x^6 + 1} multiplied by the derivative of the *inside* function x6+1x^6 + 1, which is 6x56x^5.
And, of course, the derivative of the constant CC is 00.

STEP 12

Putting it all together, we get ddx(ln(x6+1)+C)=1x6+16x5+0=6x5x6+1.\frac{d}{dx} (\ln(x^6 + 1) + C) = \frac{1}{x^6 + 1} \cdot 6x^5 + 0 = \frac{6x^5}{x^6 + 1}.

STEP 13

This **matches** our original integrand, so we know our integration is correct!

STEP 14

6x5x6+1dx=ln(x6+1)+C\int \frac{6 x^{5}}{x^{6}+1} d x = \ln(x^6 + 1) + C

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