Math

QuestionFind xx such that f(x)=3f(x) = -3 for the function f(x)=xf(x) = |x|.

Studdy Solution

STEP 1

Assumptions1. The function is defined as f(x)=xf(x)=|x| . We are given that f(x)=3f(x)=-3

STEP 2

The absolute value function f(x)=xf(x)=|x| is defined as followsf(x)={xif x0xif x<0f(x) =\begin{cases}x & \text{if } x \geq0 \\ -x & \text{if } x <0\end{cases}

STEP 3

We are given that f(x)=3f(x)=-3. However, the absolute value of any real number is always non-negative. This means that f(x)f(x) can never be negative.

STEP 4

Therefore, there is no real number xx for which f(x)=3f(x)=-3 when f(x)=xf(x)=|x|.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord