Math

QuestionFind the increase in carbon dioxide levels from 307 ppm in 1959 to 377 ppm in 2005, and calculate the percent increase. Round to the nearest tenth of a percent. Increase: parts per million, Percent increase: %\%

Studdy Solution

STEP 1

Assumptions1. The initial carbon dioxide level in1959 was307 parts per million (ppm). . The carbon dioxide level in2005 was377 ppm.
3. We need to find the increase in carbon dioxide levels and the percent of increase.

STEP 2

First, we need to find the increase in carbon dioxide levels. We can do this by subtracting the initial level from the final level.
IncreaseinCO2levels=FinallevelInitiallevelIncrease\, in\, CO2\, levels = Final\, level - Initial\, level

STEP 3

Now, plug in the given values for the initial and final levels to calculate the increase in carbon dioxide levels.
IncreaseinCO2levels=377ppm307ppmIncrease\, in\, CO2\, levels =377\, ppm -307\, ppm

STEP 4

Calculate the increase in carbon dioxide levels.
IncreaseinCO2levels=377ppm307ppm=70ppmIncrease\, in\, CO2\, levels =377\, ppm -307\, ppm =70\, ppm

STEP 5

Now that we have the increase in carbon dioxide levels, we can find the percent of increase. This can be done by dividing the increase by the initial level and then multiplying by100 to get a percentage.
Percentincrease=(IncreaseinCO2levelsInitiallevel)×100%Percent\, increase = \left(\frac{Increase\, in\, CO2\, levels}{Initial\, level}\right) \times100\%

STEP 6

Plug in the values for the increase in carbon dioxide levels and the initial level to calculate the percent increase.
Percentincrease=(70ppm307ppm)×100%Percent\, increase = \left(\frac{70\, ppm}{307\, ppm}\right) \times100\%

STEP 7

Calculate the percent increase.
Percentincrease=(70ppm307ppm)×100%=22.%Percent\, increase = \left(\frac{70\, ppm}{307\, ppm}\right) \times100\% =22.\%

STEP 8

Round the percent increase to the nearest tenth of a percent.
Percentincrease=22.8%22.8%Percent\, increase =22.8\% \approx22.8\%The increase in carbon dioxide levels is70 ppm and the percent of increase is22.8%.

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