Math

QuestionCalculate the power and express it in rectangular form: [5(cos30+isin30)]4[5(\cos 30^{\circ}+i \sin 30^{\circ})]^{4}.

Studdy Solution

STEP 1

Assumptions1. We are given a complex number in polar form 5(cos30+isin30)5(\cos30^{\circ}+i \sin30^{\circ}). . We are asked to find the fourth power of this complex number.
3. The result should be written in rectangular form.

STEP 2

First, we need to use De Moivre's theorem to find the power of a complex number in polar form. De Moivre's theorem states that if z=r(cosθ+isinθ)z=r(\cos \theta +i \sin \theta), then zn=rn(cosnθ+isinnθ)z^n=r^n(\cos n\theta +i \sin n\theta).
So, we have[5(cos30+isin30)]4=54[cos(4×30)+isin(4×30)]\left[5\left(\cos30^{\circ}+i \sin30^{\circ}\right)\right]^{4} =5^4 \left[\cos \left(4 \times30^{\circ}\right)+i \sin \left(4 \times30^{\circ}\right)\right]

STEP 3

Now, calculate the values.
5^ \left[\cos \left( \times30^{\circ}\right)+i \sin \left( \times30^{\circ}\right)\right] =625 \left[\cos120^{\circ}+i \sin120^{\circ}\right]

STEP 4

We know that cos120=12\cos120^{\circ} = -\frac{1}{2} and sin120=32\sin120^{\circ} = \frac{\sqrt{3}}{2}.
So, we have625[cos120+isin120]=625[12+i32]625 \left[\cos120^{\circ}+i \sin120^{\circ}\right] =625 \left[-\frac{1}{2}+i \frac{\sqrt{3}}{2}\right]

STEP 5

Now, multiply the real and imaginary parts by625 to convert the complex number to rectangular form.
625[12+i32]=6252+i62532625 \left[-\frac{1}{2}+i \frac{\sqrt{3}}{2}\right] = -\frac{625}{2}+i \frac{625\sqrt{3}}{2}

STEP 6

implify the expression.
6252+i62532=312.5+i312.53-\frac{625}{2}+i \frac{625\sqrt{3}}{2} = -312.5 + i312.5\sqrt{3} So, the fourth power of the given complex number in rectangular form is 312.5+i312.53-312.5 + i312.5\sqrt{3}.

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