Math

QuestionCalculate the value of csc1(2)\csc^{-1}(-2).

Studdy Solution

STEP 1

Assumptions1. The problem asks for the exact value of the inverse cosecant of -. . The range of the inverse cosecant function, csc1(x)\csc^{-1}(x), is (,π/][π/,)(-\infty, -\pi/] \cup [\pi/, \infty).
3. The domain of the inverse cosecant function, csc1(x)\csc^{-1}(x), is (,1][1,)(-\infty, -1] \cup [1, \infty).

STEP 2

We know that the cosecant function is the reciprocal of the sine function. So, we can rewrite the problem in terms of sine.
csc1(2)=sin1(12)\csc^{-1}(-2) = \sin^{-1}\left(\frac{-1}{2}\right)

STEP 3

Now, we need to find the angle whose sine is 1/2-1/2. We know that sin(π/6)=1/2\sin(\pi/6) =1/2, but since we want the negative value, we need to consider the angles in the third and fourth quadrants where the sine function is negative.

STEP 4

In the third quadrant, the angle that gives us a sine of 1/21/2 is π+π/6=7π/6\pi + \pi/6 =7\pi/6. In the fourth quadrant, the angle that gives us a sine of 1/21/2 is 2ππ/6=11π/62\pi - \pi/6 =11\pi/6.

STEP 5

However, we need to remember the range of the inverse sine function, which is [π/2,π/2][-\pi/2, \pi/2]. Neither 7π/7\pi/ nor 11π/11\pi/ fall within this range.

STEP 6

To get an angle in the range of the inverse sine function, we can subtract 2π2\pi from π/6\pi/6 and 11π/611\pi/6 until we get an angle in the correct range.

STEP 7

Subtracting 2π2\pi from 7π/67\pi/6 gives us 5π/6-5\pi/6, which is in the range of the inverse sine function. So,
sin1(12)=5π6\sin^{-1}\left(\frac{-1}{2}\right) = -\frac{5\pi}{6}

STEP 8

Substituting this back into our original problem, we find thatcsc1(2)=5π6\csc^{-1}(-2) = -\frac{5\pi}{6}So, the exact value of the expression csc1(2)\csc^{-1}(-2) is 5π6-\frac{5\pi}{6}.

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