Math

QuestionFind cosθ\cos \theta if sinθ=45\sin \theta=\frac{4}{5} and θ\theta is in quadrant I.

Studdy Solution

STEP 1

Assumptions1. The value of sinθ\sin \theta is given as 45\frac{4}{5} . θ\theta is in quadrant I3. We are asked to find the exact value of cosθ\cos \theta
4. We will use the Pythagorean identity sinθ+cosθ=1\sin^ \theta + \cos^ \theta =1

STEP 2

First, we need to use the Pythagorean identity to express cosθ\cos \theta in terms of sinθ\sin \theta.
cos2θ=1sin2θ\cos^2 \theta =1 - \sin^2 \theta

STEP 3

Now, plug in the given value for sinθ\sin \theta to calculate cos2θ\cos^2 \theta.
cos2θ=1(5)2\cos^2 \theta =1 - \left(\frac{}{5}\right)^2

STEP 4

Calculate the square of 4\frac{4}{}.
(4)2=1625\left(\frac{4}{}\right)^2 = \frac{16}{25}

STEP 5

Substitute the value of (45)2\left(\frac{4}{5}\right)^2 into the equation for cos2θ\cos^2 \theta.
cos2θ=11625\cos^2 \theta =1 - \frac{16}{25}

STEP 6

Subtract 1625\frac{16}{25} from1 to find cos2θ\cos^2 \theta.
cos2θ=925\cos^2 \theta = \frac{9}{25}

STEP 7

Now that we have the value of cos2θ\cos^2 \theta, we can find the value of cosθ\cos \theta by taking the square root of both sides of the equation. Remember that the square root of a number can be positive or negative, but since θ\theta is in quadrant I where cosine is positive, we only take the positive root.
cosθ=cos2θ\cos \theta = \sqrt{\cos^2 \theta}

STEP 8

Plug in the value for cos2θ\cos^2 \theta to calculate cosθ\cos \theta.
cosθ=25\cos \theta = \sqrt{\frac{}{25}}

STEP 9

Calculate the square root of 925\frac{9}{25}.
cosθ=35\cos \theta = \frac{3}{5}So, the exact value of cosθ\cos \theta is 35\frac{3}{5}.

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