Math

QuestionFind the line equation through points (1,5)(1,5) and (6,3)(-6,-3). y=y=

Studdy Solution

STEP 1

Assumptions1. The line passes through the points (1,5) and (-6,-3) . The equation of a line can be written in the form y=mx+by = mx + b where m is the slope and b is the y-intercept.

STEP 2

First, we need to find the slope of the line. The slope (m) can be calculated using the formulam=y2y1x2x1m = \frac{y2 - y1}{x2 - x1}

STEP 3

Now, plug in the given values for the coordinates of the two points to calculate the slope.
m=3561m = \frac{-3 -5}{-6 -1}

STEP 4

Calculate the slope.
m=87=87m = \frac{-8}{-7} = \frac{8}{7}

STEP 5

Now that we have the slope, we can find the y-intercept (b) using the formulab=ymxb = y - mxWe can use the coordinates of either of the two given points. Let's use the point (1,5).

STEP 6

Plug in the values for y, m, and x to calculate the y-intercept.
b=58×1b =5 - \frac{8}{} \times1

STEP 7

Calculate the y-intercept.
b=57=3577=277b =5 - \frac{}{7} = \frac{35}{7} - \frac{}{7} = \frac{27}{7}

STEP 8

Now that we have the slope and the y-intercept, we can write the equation of the line.
y=mx+by = mx + b

STEP 9

Plug in the values for m and b to write the equation of the line.
y=87x+277y = \frac{8}{7}x + \frac{27}{7}So, the equation of the line that passes through the points (,5) and (-6,-3) is y=87x+277y = \frac{8}{7}x + \frac{27}{7}.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord