Math

QuestionFind tanB\tan B given a=5a=5, b=12b=12, and c=13c=13. Also, sinB=1213\sin B=\frac{12}{13}, cosB=513\cos B=\frac{5}{13}.

Studdy Solution

STEP 1

Assumptions1. The triangle is a right triangle. . The sides of the triangle are a=5, b=12, and c=13.
3. The angle B is the angle opposite side b.
4. The sine of angle B is given by sinB=bc\sin B = \frac{b}{c}.
5. The cosine of angle B is given by cosB=ac\cos B = \frac{a}{c}.
6. The tangent of angle B is given by tanB=ba\tan B = \frac{b}{a}.

STEP 2

We have already been given the sine and cosine of angle B. We need to calculate the tangent of angle B.The formula for the tangent of an angle in a right triangle istanB=ba\tan B = \frac{b}{a}

STEP 3

Now, plug in the given values for sides a and b to calculate the tangent of angle B.
tanB=125\tan B = \frac{12}{5}

STEP 4

implify the expression to get the value of tanB\tan B.
tanB=12=2.4\tan B = \frac{12}{} =2.4The tangent of angle B is2.4.

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