Math  /  Algebra

QuestionFind functions ff and gg so that fg=Hf \circ g=H. H(x)=(5x+2)4H(x)=(5 x+2)^{4}
Choose the correct pair of functions. A. f(x)=x4,g(x)=x25f(x)=\sqrt[4]{x}, g(x)=\frac{x-2}{5} C. f(x)=x25,g(x)=x4f(x)=\frac{x-2}{5}, g(x)=\sqrt[4]{x} BB. f(x)=x4,g(x)=5x+2f(x)=x^{4}, g(x)=5 x+2 D. f(x)=5x+2,g(x)=x4f(x)=5 x+2, g(x)=x^{4}

Studdy Solution

STEP 1

1. We are given the composite function H(x)=(5x+2)4 H(x) = (5x + 2)^4 .
2. We need to find functions f f and g g such that fg=H f \circ g = H .

STEP 2

1. Understand the structure of the function H(x) H(x) .
2. Analyze each option to determine if fg=H f \circ g = H .
3. Verify the correct pair of functions.

STEP 3

Understand the structure of H(x)=(5x+2)4 H(x) = (5x + 2)^4 .
- The function H(x) H(x) is a composition of two operations: first, a linear transformation 5x+2 5x + 2 , and second, raising the result to the 4th power.

STEP 4

Analyze Option A:
- f(x)=x4 f(x) = \sqrt[4]{x} , g(x)=x25 g(x) = \frac{x-2}{5} - Compute f(g(x))=f(x25)=x254 f(g(x)) = f\left(\frac{x-2}{5}\right) = \sqrt[4]{\frac{x-2}{5}}
This does not match H(x)=(5x+2)4 H(x) = (5x + 2)^4 .

STEP 5

Analyze Option B:
- f(x)=x4 f(x) = x^4 , g(x)=5x+2 g(x) = 5x + 2 - Compute f(g(x))=f(5x+2)=(5x+2)4 f(g(x)) = f(5x + 2) = (5x + 2)^4
This matches H(x)=(5x+2)4 H(x) = (5x + 2)^4 .

STEP 6

Analyze Option C:
- f(x)=x25 f(x) = \frac{x-2}{5} , g(x)=x4 g(x) = \sqrt[4]{x} - Compute f(g(x))=f(x4)=x425 f(g(x)) = f(\sqrt[4]{x}) = \frac{\sqrt[4]{x} - 2}{5}
This does not match H(x)=(5x+2)4 H(x) = (5x + 2)^4 .

STEP 7

Analyze Option D:
- f(x)=5x+2 f(x) = 5x + 2 , g(x)=x4 g(x) = x^4 - Compute f(g(x))=f(x4)=5(x4)+2 f(g(x)) = f(x^4) = 5(x^4) + 2
This does not match H(x)=(5x+2)4 H(x) = (5x + 2)^4 .

STEP 8

Verify the correct pair of functions:
- From the analysis, Option B is the correct pair: f(x)=x4 f(x) = x^4 , g(x)=5x+2 g(x) = 5x + 2 .
The correct pair of functions is:
B \boxed{B}

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord