Math

QuestionCalculate f(x)f(-x) for the function f(x)=2x2+3x+3f(x)=-2 x^{2}+3 x+3.

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=x+3x+3f(x)=- x^{}+3 x+3 . We are asked to find the value of f(x)f(-x)

STEP 2

To find f(x)f(-x), we need to substitute x-x in place of xx in the function f(x)f(x).
So, f(x)=2(x)2+(x)+f(-x) = -2(-x)^{2} +(-x) +

STEP 3

implify the equation by applying the power to x-x in the first term and multiplying x-x by3 in the second term.
f(x)=2x23x+3f(-x) = -2x^{2} -3x +3

STEP 4

So, the value of f(x)f(-x) when f(x)=2x2+3x+3f(x)=-2 x^{2}+3 x+3 is f(x)=2x23x+3f(-x) = -2x^{2} -3x +3.

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