Math  /  Geometry

QuestionFind DFD F.
Write your answer as an integer or as a decimal rounded to the nearest tenth.

Studdy Solution

STEP 1

What is this asking? We're looking for the length of one side of a right triangle when we know the hypotenuse and an angle. Watch out! Make sure your calculator is in degree mode, not radians!

STEP 2

1. Set up the cosine ratio.
2. Solve for the unknown side.

STEP 3

Alright, let's **dive in**!
We've got a right triangle, a known angle, and we're looking for the side *adjacent* to that angle.
This screams "**cosine**"!
Remember, cosine is all about the adjacent side and the hypotenuse.

STEP 4

The cosine of an angle in a right triangle is defined as the ratio of the length of the adjacent side to the length of the hypotenuse.
So, we can write: cos(D)=adjacent sidehypotenuse \cos(\angle D) = \frac{\text{adjacent side}}{\text{hypotenuse}}

STEP 5

Let's **plug in** what we know!
Our angle D\angle D is **61 degrees**, the adjacent side is DFDF, which is what we're trying to find, and the hypotenuse DEDE is **5.8**.
This gives us: cos(61)=DF5.8 \cos(61^\circ) = \frac{DF}{5.8}

STEP 6

Now, we want to get DFDF all by itself.
To do this, we'll **multiply both sides** of the equation by **5.8**.
Remember, what we do to one side, we *must* do to the other to keep things balanced!
This gives us: 5.8cos(61)=5.8DF5.8 5.8 \cdot \cos(61^\circ) = 5.8 \cdot \frac{DF}{5.8}

STEP 7

On the right side, the **5.8's divide to one**, leaving us with just DFDF: 5.8cos(61)=DF 5.8 \cdot \cos(61^\circ) = DF

STEP 8

Now, grab your calculator and make sure it's in **degree mode**!
Calculate the value of 5.8cos(61)5.8 \cdot \cos(61^\circ): DF=5.8cos(61)5.80.48482.808 DF = 5.8 \cdot \cos(61^\circ) \approx 5.8 \cdot 0.4848 \approx 2.808

STEP 9

Rounding to the nearest tenth gives us our **final answer**: DF2.8 DF \approx 2.8

STEP 10

DFDF is approximately **2.8**.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord