Math

QuestionFind the inverse of the function f(x)=4x2f(x)=-4 x^{2} and express it as f1(x)=f^{-1}(x)=.

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=4xf(x)=-4 x^{} . We are asked to find the inverse of the function f(x)f(x)

STEP 2

The first step in finding the inverse of a function is to replace f(x)f(x) with yy. This gives usy=4x2y = -4x^{2}

STEP 3

The next step is to swap xx and yy. This gives usx=y2x = -y^{2}

STEP 4

Now we need to solve this equation for yy to get the inverse function. To do this, we first divide both sides by 4-4x4=y2\frac{x}{-4} = y^{2}

STEP 5

Next, we take the square root of both sides. However, we must remember that when we take the square root of a square, we get two solutions a positive and a negative. Therefore, we gety=x4andy=x4y = \sqrt{\frac{-x}{4}} \quad \text{and} \quad y = -\sqrt{\frac{-x}{4}}

STEP 6

implify the square root by taking the square root of4 in the denominatory=x2andy=x2y = \sqrt{\frac{-x}{2}} \quad \text{and} \quad y = -\sqrt{\frac{-x}{2}}

STEP 7

Now, we have found the inverse of the function f(x)=4x2f(x)=-4 x^{2}. However, we must remember that the original function f(x)f(x) is a function, which means it passes the vertical line test. The inverse, however, does not pass the vertical line test, which means it is not a function. Therefore, we usually choose one branch of the inverse to be the function. In this case, we choose the positive branchf1(x)=x2f^{-1}(x) = \sqrt{\frac{-x}{2}}

STEP 8

To draw the inverse function, we can plot the points that satisfy the equation f1(x)=x2f^{-1}(x) = \sqrt{\frac{-x}{2}}. We can also reflect the graph of the original function f(x)=4x2f(x)=-4 x^{2} over the line y=xy=x to get the graph of the inverse function.

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