Math

QuestionFind and simplify for f(x)=7x2f(x)=7x-2: (A) f(x+h)f(x+h), (B) f(x+h)f(x)f(x+h)-f(x), (C) f(x+h)f(x)h\frac{f(x+h)-f(x)}{h}.

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=7xf(x)=7x- . We are asked to find and simplify f(x+h)f(x+h), f(x+h)f(x)f(x+h)-f(x), and f(x+h)f(x)h\frac{f(x+h)-f(x)}{h}

STEP 2

First, we need to find f(x+h)f(x+h). We can do this by replacing every instance of xx in the function f(x)f(x) with (x+h)(x+h).
f(x+h)=7(x+h)2f(x+h) =7(x+h) -2

STEP 3

Now, distribute the 77 to both xx and hh inside the parentheses.
f(x+h)=7x+7h2f(x+h) =7x +7h -2

STEP 4

Now, we need to find f(x+h)f(x)f(x+h)-f(x). We can do this by subtracting f(x)f(x) from f(x+h)f(x+h).
f(x+h)f(x)=(7x+7h2)(7x2)f(x+h)-f(x) = (7x +7h -2) - (7x -2)

STEP 5

implify the expression by performing the subtraction.
f(x+h)f(x)=7hf(x+h)-f(x) =7h

STEP 6

Now, we need to find f(x+h)f(x)h\frac{f(x+h)-f(x)}{h}. We can do this by dividing f(x+h)f(x)f(x+h)-f(x) by hh.
f(x+h)f(x)h=hh\frac{f(x+h)-f(x)}{h} = \frac{h}{h}

STEP 7

implify the expression by cancelling out the hh in the numerator and the denominator.
f(x+h)f(x)h=7\frac{f(x+h)-f(x)}{h} =7So, we have found that(A) f(x+h)=7x+7h2f(x+h) =7x +7h -2 (B) f(x+h)f(x)=7hf(x+h)-f(x) =7h (C) f(x+h)f(x)h=7\frac{f(x+h)-f(x)}{h} =7

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