Math

Question Find all values of xx that solve the equation 2x213x+36=152x^2 - 13x + 36 = 15.

Studdy Solution

STEP 1

Assumptions
1. The function given is f(x)=2x213x+36f(x) = 2x^2 - 13x + 36.
2. We need to find the values of xx such that f(x)=15f(x) = 15.

STEP 2

To find the values of xx for which f(x)=15f(x) = 15, we set the function equal to 15 and solve for xx.
2x213x+36=152x^2 - 13x + 36 = 15

STEP 3

Subtract 15 from both sides of the equation to set the right side to zero, which is necessary for solving a quadratic equation.
2x213x+3615=02x^2 - 13x + 36 - 15 = 0

STEP 4

Simplify the equation by combining like terms.
2x213x+21=02x^2 - 13x + 21 = 0

STEP 5

We now have a quadratic equation in standard form. We can try to factor this equation, or use the quadratic formula to find the values of xx. Let's attempt to factor first.

STEP 6

Look for two numbers that multiply to 2×212 \times 21 (which is 42) and add up to -13 (the coefficient of the xx term).

STEP 7

The numbers that satisfy these conditions are -6 and -7 because (6)×(7)=42(-6) \times (-7) = 42 and (6)+(7)=13(-6) + (-7) = -13.

STEP 8

Rewrite the middle term of the quadratic equation using the numbers found in STEP_7.
2x26x7x+21=02x^2 - 6x - 7x + 21 = 0

STEP 9

Factor by grouping. Group the first two terms together and the last two terms together.
(2x26x)+(7x+21)=0(2x^2 - 6x) + (-7x + 21) = 0

STEP 10

Factor out the greatest common factor from each group.
2x(x3)7(x3)=02x(x - 3) - 7(x - 3) = 0

STEP 11

Now, factor out the common binomial factor (x3)(x - 3).
(2x7)(x3)=0(2x - 7)(x - 3) = 0

STEP 12

Apply the zero-product property, which states that if a product of two factors is zero, then at least one of the factors must be zero.
2x7=0orx3=02x - 7 = 0 \quad \text{or} \quad x - 3 = 0

STEP 13

Solve each equation for xx.
First, solve 2x7=02x - 7 = 0:
2x=72x = 7
x=72x = \frac{7}{2}
x=3.5x = 3.5

STEP 14

Now, solve x3=0x - 3 = 0:
x=3x = 3

STEP 15

The solutions to the equation f(x)=15f(x) = 15 are x=3.5x = 3.5 and x=3x = 3.
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