Math

QuestionComplete the isotope table for 14C{ }^{14} \mathrm{C}, 16 N{ }^{16} \mathrm{~N}, 21 F{ }^{21} \mathrm{~F} using atomic mass - atomic number.

Studdy Solution

STEP 1

Assumptions1. Each symbol represents an isotope of a particular element. . The isotopes are neutral.
3. The atomic mass is the number on top.
4. The atomic number is typically the number of protons in an element's nucleus.
5. The number of neutrons can be calculated using the general formula (atomic mass - atomic number).

STEP 2

First, we need to identify the atomic number of each isotope. The atomic number is the number of protons in an element's nucleus. We can find this by referring to the periodic table.
For 14C{ }^{14} \mathrm{C}, 16 { }^{16} \mathrm{~}, and 21 { }^{21} \mathrm{~}, the atomic numbers (protons) are6,7, and9 respectively.

STEP 3

Next, we need to identify the atomic mass of each isotope. The atomic mass is the number on top.
For 14C{ }^{14} \mathrm{C}, 16 { }^{16} \mathrm{~}, and 21 { }^{21} \mathrm{~}, the atomic masses are14,16, and21 respectively.

STEP 4

Now, we can calculate the number of neutrons in each isotope using the general formula (atomic mass - atomic number).
For 14C{ }^{14} \mathrm{C}, 16 { }^{16} \mathrm{~}, and 21 { }^{21} \mathrm{~}, the number of neutrons are (14-6), (16-7), and (21-9) respectively.

STEP 5

Calculate the number of neutrons.
For 14C{ }^{14} \mathrm{C}, 16 { }^{16} \mathrm{~}, and 21 { }^{21} \mathrm{~}, the number of neutrons are8,9, and12 respectively.

STEP 6

Since the isotopes are neutral, the number of electrons in each isotope is equal to the number of protons (atomic number).
For 14C{ }^{14} \mathrm{C}, 16 { }^{16} \mathrm{~}, and 21 { }^{21} \mathrm{~}, the number of electrons are6,, and9 respectively.
The completed table is\begin{tabular}{|l|l|l|l|} \hline Symbol & 14C{ }^{14} \mathrm{C} & 16 { }^{16} \mathrm{~} & 21 { }^{21} \mathrm{~} \\ \hline Protons &6 & &9 \\ \hline Neutrons &8 &9 &12 \\ \hline Electrons &6 & &9 \\ \hline Atomic \# &6 & &9 \\ \hline Mass \# &14 &16 &21 \\ \hline\end{tabular}

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