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Math  /  Algebra

QuestionFactories often add filler when making meatballs sold by the bag. One factory obtained 135 kg of beef from overseas. They want to add 1.3 oz of filler for each pound of beef. How many ounces of filler will the factory need in order to make meatballs out of this shipment of beef?
Use 1lb=0.45 kg1 \mathrm{lb}=0.45 \mathrm{~kg} and do not round any computations. □\square oz

Studdy Solution

STEP 1

1. The factory has 135 kg of beef.
2. 1 pound (lb) is equivalent to 0.45 kilograms (kg).
3. The factory adds 1.3 ounces (oz) of filler for each pound of beef.
4. We need to find the total ounces of filler required.

STEP 2

1. Convert kilograms of beef to pounds.
2. Calculate the total ounces of filler needed.

STEP 3

Convert kilograms of beef to pounds.
Given: 1 lb=0.45 kg 1 \text{ lb} = 0.45 \text{ kg}
To find the number of pounds of beef: Pounds of beef=135 kg0.45 kg/lb \text{Pounds of beef} = \frac{135 \text{ kg}}{0.45 \text{ kg/lb}}
Pounds of beef=300 lb \text{Pounds of beef} = 300 \text{ lb}

STEP 4

Calculate the total ounces of filler needed.
Given: Filler per pound=1.3 oz \text{Filler per pound} = 1.3 \text{ oz}
Total ounces of filler: Total filler=300 lb×1.3 oz/lb \text{Total filler} = 300 \text{ lb} \times 1.3 \text{ oz/lb}
Total filler=390 oz \text{Total filler} = 390 \text{ oz}
The factory will need:
390 oz \boxed{390} \text{ oz}

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