Math

QuestionSolve the equation by factoring: 5w2=26w+245 w^{2} = 26 w + 24.

Studdy Solution

STEP 1

Assumptions1. We are given the equation 5w=26w+245w^{} =26w +24 . We are asked to solve this equation by factoring

STEP 2

First, we need to rearrange the equation so that it equals zero. This is because factoring is a method used to solve equations in the form ax2+bx+c=0ax^2 + bx + c =0.5w226w24=05w^{2} -26w -24 =0

STEP 3

Now, we need to factor the equation. Factoring is the process of breaking down an equation into its simplest terms, or factors. In this case, we are looking for two numbers that multiply to 120-120 (which is 5×245 \times -24) and add to 26-26.

STEP 4

The two numbers that satisfy these conditions are 8-8 and 1515. So, we can rewrite the middle term of the equation as 8w+15w-8w +15w.
w28w+15w24=0w^{2} -8w +15w -24 =0

STEP 5

Now, we can factor by grouping. Grouping is a method where we group the terms two at a time and factor out the greatest common factor.w(5w8)+3(5w8)=0w(5w -8) +3(5w -8) =0

STEP 6

Now, we can see that the terms in the parentheses are the same. So, we can factor out 5w85w -8.
(5w8)(w+3)=0(5w -8)(w +3) =0

STEP 7

Now, we can set each factor equal to zero and solve for ww.
5w=0andw+3=05w - =0 \quad \text{and} \quad w +3 =0

STEP 8

olve the first equation for ww.
5w=85w =8w=85w = \frac{8}{5}

STEP 9

olve the second equation for ww.
w=3w = -3The solutions to the equation are w=85w = \frac{8}{5} and w=3w = -3.

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