Math

QuestionFactor the expression: x2+4x+3x^{2}+4x+3.

Studdy Solution

STEP 1

Assumptions1. The given expression is x+4x+3x^{}+4x+3 . We need to factorize this expression

STEP 2

The given expression is a quadratic expression. A quadratic expression of the form ax2+bx+cax^{2}+bx+c can be factored as (xp)(xq)(x-p)(x-q), where pp and qq are the roots of the equation ax2+bx+c=0ax^{2}+bx+c=0.

STEP 3

To find the roots of the equation, we need to solve the equation x2+x+3=0x^{2}+x+3=0. The roots of this equation can be found using the formula x=b±b2ac2ax = \frac{-b \pm \sqrt{b^{2}-ac}}{2a}, where aa, bb, and cc are the coefficients of x2x^{2}, xx, and the constant term respectively.

STEP 4

In our equation, a=1a=1, b=4b=4, and c=3c=3. Substituting these values into the formula, we getx=4±424(1)(3)2(1)x = \frac{-4 \pm \sqrt{4^{2}-4(1)(3)}}{2(1)}

STEP 5

implify the expression under the square rootx=4±16122x = \frac{-4 \pm \sqrt{16-12}}{2}

STEP 6

Further simplify the expressionx=4±42x = \frac{-4 \pm \sqrt{4}}{2}

STEP 7

Calculate the square rootx=4±22x = \frac{-4 \pm2}{2}

STEP 8

This gives us two solutionsx=4+22=1x = \frac{-4 +2}{2} = -1andx=422=3x = \frac{-4 -2}{2} = -3

STEP 9

So, the roots of the equation are - and -3. Therefore, the factored form of the expression x2+4x+3x^{2}+4x+3 is (x+)(x+3)(x+)(x+3).
The factored form of x2+4x+3x^{2}+4x+3 is (x+)(x+3)(x+)(x+3).

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