Math  /  Algebra

QuestionFactor out the greatest common factor. 7×(a+2b)(a+2b)7 \times(a+2 b)-(a+2 b)

Studdy Solution

STEP 1

What is this asking? We're trying to simplify an expression by pulling out the biggest shared piece between two terms. Watch out! Don't forget that (a+2b)(a + 2b) is a *single* term, just like xx or yy would be!

STEP 2

1. Rewrite the expression
2. Identify and factor out the GCF

STEP 3

We've got 7(a+2b)(a+2b)7 \cdot (a+2b) - (a+2b).
Notice how (a+2b)(a+2b) appears in both parts of our expression?
That's a big clue!
To make it even clearer, let's rewrite the second part.
Remember, anything multiplied by **1** stays the same, so we can write (a+2b)(a+2b) as 1(a+2b)1 \cdot (a+2b).
This gives us 7(a+2b)1(a+2b)7 \cdot (a + 2b) - 1 \cdot (a+2b).
Now the common factor (a+2b)(a+2b) is super obvious!

STEP 4

Now, we **factor out** (a+2b)(a+2b).
Imagine (a+2b)(a+2b) is like a golden ticket everyone wants!
Both the **7** and the **-1** have this golden ticket, and we're going to take it from them.
When we take (a+2b)(a+2b) from 7(a+2b)7 \cdot (a+2b), we're left with just **7**.
When we take (a+2b)(a+2b) from 1(a+2b)-1 \cdot (a+2b), we're left with 1-1.
So, we write it like this: (a+2b)(71)(a+2b)(7-1).

STEP 5

Inside the second set of parentheses, we have 717-1, which simplifies to **6**.
So, our fully factored expression is (a+2b)6(a+2b) \cdot 6, or more conventionally, 6(a+2b)6(a+2b).
Boom!

STEP 6

6(a+2b)6(a+2b)

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