Math  /  Algebra

QuestionFactor. 9y2+48y+649 y^{2}+48 y+64

Studdy Solution

STEP 1

1. The expression is a quadratic trinomial.
2. The expression can be factored into the form (ay+b)2(ay + b)^2 if it is a perfect square trinomial.
3. If the expression is not a perfect square trinomial, it can be factored using other methods such as grouping or the quadratic formula.

STEP 2

1. Check if the trinomial is a perfect square.
2. Factor the trinomial if it is a perfect square.

STEP 3

Check if the trinomial 9y2+48y+649y^2 + 48y + 64 is a perfect square trinomial. A perfect square trinomial takes the form (ay+b)2=a2y2+2aby+b2(ay + b)^2 = a^2y^2 + 2aby + b^2.
- Identify a2=9y2a^2 = 9y^2, so a=3ya = 3y. - Identify b2=64b^2 = 64, so b=8b = 8. - Check if 2ab=48y2ab = 48y.
Calculate 2ab2ab:
23y8=48y 2 \cdot 3y \cdot 8 = 48y
Since 2ab=48y2ab = 48y, the trinomial is a perfect square.

STEP 4

Since the trinomial is a perfect square, factor it as (ay+b)2(ay + b)^2.
(3y+8)2 (3y + 8)^2
Thus, the factorization of the trinomial 9y2+48y+649y^2 + 48y + 64 is:
(3y+8)2 \boxed{(3y + 8)^2}

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