Math  /  Algebra

QuestionEXERCISE
1. UME 2906 Que 25 simplify (25) 1x×(27)+(121)12×(625)14\frac{1}{x} \times(27)^{\prime}+(121)^{-\frac{1}{2}} \times(625)^{-\frac{1}{4}}

Studdy Solution

STEP 1

1. We are asked to simplify the given expression.
2. The expression involves exponents and roots that can be simplified using exponent rules.
3. The notation (27)(27)^{\prime} is assumed to mean the derivative of a constant, which is zero.

STEP 2

1. Simplify each term in the expression separately.
2. Combine the simplified terms to achieve the final simplified expression.

STEP 3

Simplify the first term 1x×(27)\frac{1}{x} \times (27)^{\prime}.
Since (27)(27)^{\prime} is the derivative of a constant, it equals zero:
1x×0=0\frac{1}{x} \times 0 = 0

STEP 4

Simplify the second term (121)12×(625)14(121)^{-\frac{1}{2}} \times (625)^{-\frac{1}{4}}.
First, simplify (121)12(121)^{-\frac{1}{2}}:
(121)12=1121=111(121)^{-\frac{1}{2}} = \frac{1}{\sqrt{121}} = \frac{1}{11}
Next, simplify (625)14(625)^{-\frac{1}{4}}:
(625)14=16254=15(625)^{-\frac{1}{4}} = \frac{1}{\sqrt[4]{625}} = \frac{1}{5}
Now, multiply the simplified terms:
111×15=155\frac{1}{11} \times \frac{1}{5} = \frac{1}{55}

STEP 5

Combine the simplified terms from STEP_1 and STEP_2:
0+155=1550 + \frac{1}{55} = \frac{1}{55}
The simplified expression is:
155\boxed{\frac{1}{55}}

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