Math  /  Data & Statistics

QuestionEvaluate z=p^1p^20SEz=\frac{\hat{p}_{1}-\hat{p}_{2}-0}{S E} for p^1=0.413,p^2=0.343\hat{p}_{1}=0.413, \hat{p}_{2}=0.343, and SE=0.165S E=0.165 z=z= \square (Round to two decimal places as needed.)

Studdy Solution

STEP 1

What is this asking? We're simply plugging numbers into a formula and calculating the result!
Specifically, we're finding a value called zz by substituting given values for p^1\hat{p}_{1}, p^2\hat{p}_{2}, and SESE. Watch out! Be careful with the order of operations, especially the subtraction in the numerator.
Also, remember to round the final answer to two decimal places.

STEP 2

1. Substitute the values
2. Calculate the numerator
3. Calculate the final result

STEP 3

Alright, let's **kick things off** by plugging in the **given values** into our formula for zz.
We have p^1=0.413\hat{p}_{1} = \textbf{0.413}, p^2=0.343\hat{p}_{2} = \textbf{0.343}, and SE=0.165SE = \textbf{0.165}.
So, our formula becomes: z=0.4130.34300.165 z = \frac{0.413 - 0.343 - 0}{0.165}

STEP 4

Now, let's **tackle the numerator**.
We have 0.4130.34300.413 - 0.343 - 0.
Remember, subtracting zero doesn't change a number!
So, we just need to calculate 0.4130.3430.413 - 0.343. 0.4130.343=0.07 0.413 - 0.343 = \textbf{0.07} So, our numerator is **0.07**.

STEP 5

With our **numerator simplified**, our equation looks like this: z=0.070.165 z = \frac{0.07}{0.165} Now, we just need to **perform the division** to find our **final result**: z=0.070.1650.4242424... z = \frac{0.07}{0.165} \approx \textbf{0.4242424...}

STEP 6

Almost there!
The problem asks us to **round to two decimal places**.
Looking at our result, the third decimal place is 4, which is less than 5, so we round down.
Our **final answer**, rounded to two decimal places, is 0.42\textbf{0.42}.

STEP 7

Therefore, z0.42z \approx 0.42.

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