QuestionEvaluate: $y(x+y)$ for $x=\frac{4}{3}$ and $y=2$ .

Studdy Solution

STEP 1

Assumptions1. The function to evaluate is $y(x+y)$ . The value of $x$ is $\frac{4}{3}$
3. The value of $y$ is $$

STEP 2

We need to substitute the given values of $x$ and $y$ into the function. $y(x+y) =2\left(\frac{4}{} +2\right)$

STEP 3

Now, we simplify the expression inside the parentheses.
$2\left(\frac{}{3} +2\right) =2\left(\frac{}{3} + \frac{6}{3}\right)$

STEP 4

Add the fractions inside the parentheses.
$2\left(\frac{4}{3} + \frac{6}{3}\right) =2 \times \frac{10}{3}$

STEP 5

Multiply the fraction by2 to get the final answer.
$2 \times \frac{10}{3} = \frac{20}{3}$ So, $y(x+y)$ evaluates to $\frac{20}{3}$ when $x=\frac{4}{3}$ and $y=2$ .

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QuestionEvaluate: $y(x+y)$ for $x=\frac{4}{3}$ and $y=2$ .

Studdy Solution

STEP 1

Assumptions1. The function to evaluate is $y(x+y)$ . The value of $x$ is $\frac{4}{3}$
3. The value of $y$ is $$

STEP 2

We need to substitute the given values of $x$ and $y$ into the function. $y(x+y) =2\left(\frac{4}{} +2\right)$

STEP 3

Now, we simplify the expression inside the parentheses.
$2\left(\frac{}{3} +2\right) =2\left(\frac{}{3} + \frac{6}{3}\right)$

STEP 4

Add the fractions inside the parentheses.
$2\left(\frac{4}{3} + \frac{6}{3}\right) =2 \times \frac{10}{3}$

STEP 5

Multiply the fraction by2 to get the final answer.
$2 \times \frac{10}{3} = \frac{20}{3}$ So, $y(x+y)$ evaluates to $\frac{20}{3}$ when $x=\frac{4}{3}$ and $y=2$ .

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QuestionEvaluate: y(x+y)y(x+y)y(x+y) for x=43x=\frac{4}{3}x=34​ and y=2y=2y=2.

Studdy Solution

STEP 1

Assumptions1. The function to evaluate is y(x+y)y(x+y)y(x+y). The value of xxx is 43\frac{4}{3}34​3. The value of yyy is $$

STEP 2

We need to substitute the given values of xxx and yyy into the function.y(x+y)=2(4+2)y(x+y) =2\left(\frac{4}{} +2\right)y(x+y)=2(4​+2)

STEP 3

Now, we simplify the expression inside the parentheses.2(3+2)=2(3+63)2\left(\frac{}{3} +2\right) =2\left(\frac{}{3} + \frac{6}{3}\right)2(3​+2)=2(3​+36​)

STEP 4

Add the fractions inside the parentheses.2(43+63)=2×1032\left(\frac{4}{3} + \frac{6}{3}\right) =2 \times \frac{10}{3}2(34​+36​)=2×310​

STEP 5

Multiply the fraction by2 to get the final answer.2×103=2032 \times \frac{10}{3} = \frac{20}{3}2×310​=320​So, y(x+y)y(x+y)y(x+y) evaluates to 203\frac{20}{3}320​ when x=43x=\frac{4}{3}x=34​ and y=2y=2y=2.

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QuestionEvaluate: $y(x+y)$ for $x=\frac{4}{3}$ and $y=2$ .

Assumptions1. The function to evaluate is $y(x+y)$ . The value of $x$ is $\frac{4}{3}$
3. The value of $y$ is $$

We need to substitute the given values of $x$ and $y$ into the function. $y(x+y) =2\left(\frac{4}{} +2\right)$

Now, we simplify the expression inside the parentheses.
$2\left(\frac{}{3} +2\right) =2\left(\frac{}{3} + \frac{6}{3}\right)$

Add the fractions inside the parentheses.
$2\left(\frac{4}{3} + \frac{6}{3}\right) =2 \times \frac{10}{3}$

Multiply the fraction by2 to get the final answer.
$2 \times \frac{10}{3} = \frac{20}{3}$ So, $y(x+y)$ evaluates to $\frac{20}{3}$ when $x=\frac{4}{3}$ and $y=2$ .