Math  /  Calculus

QuestionEvatuate x2+1xdx\int \sqrt{x^{2}+1} x d x

Studdy Solution

STEP 1

1. The integral x2+1xdx\int \sqrt{x^{2}+1} x \, dx is a standard integral that can be solved using substitution.
2. The function inside the integral involves a composition of functions, suggesting the use of substitution.

STEP 2

1. Choose an appropriate substitution to simplify the integral.
2. Perform the substitution and simplify the integral.
3. Integrate the simplified expression.
4. Substitute back to the original variable.

STEP 3

Choose a substitution. Let u=x2+1 u = x^2 + 1 . Then, compute the differential du du :
u=x2+1 u = x^2 + 1 dudx=2x \frac{du}{dx} = 2x du=2xdx du = 2x \, dx
To match the integral, solve for xdx x \, dx :
xdx=12du x \, dx = \frac{1}{2} du

STEP 4

Substitute u u and du du into the integral:
x2+1xdx=u12du \int \sqrt{x^2 + 1} \, x \, dx = \int \sqrt{u} \cdot \frac{1}{2} \, du
Simplify the integral:
=12u1/2du = \frac{1}{2} \int u^{1/2} \, du

STEP 5

Integrate the simplified expression:
12u1/2du=1223u3/2+C \frac{1}{2} \int u^{1/2} \, du = \frac{1}{2} \cdot \frac{2}{3} u^{3/2} + C =13u3/2+C = \frac{1}{3} u^{3/2} + C

STEP 6

Substitute back to the original variable x x :
u=x2+1 u = x^2 + 1 13u3/2+C=13(x2+1)3/2+C \frac{1}{3} u^{3/2} + C = \frac{1}{3} (x^2 + 1)^{3/2} + C
The evaluated integral is:
13(x2+1)3/2+C \boxed{\frac{1}{3} (x^2 + 1)^{3/2} + C}

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