Math  /  Trigonometry

QuestionEvaluate the function f(x)=tan1(x)f(x)=\tan ^{-1}(x) when x=0x=0. Give your answer in radians. 0 π\pi 3π2\frac{3 \pi}{2} 2π2 \pi

Studdy Solution

STEP 1

What is this asking? What's the *arctangent* of zero, or in other words, what angle has a tangent of zero?
And remember, we want the answer in radians! Watch out! Make sure your calculator is set to radian mode, and don't mix up *tangent* with *arctangent*!

STEP 2

1. Define the function
2. Evaluate at x=0x = 0

STEP 3

We're given the function f(x)=tan1(x)f(x) = \tan^{-1}(x).
This is the *inverse tangent* function, also known as *arctangent*.
It's asking: "What angle has a tangent of xx?".

STEP 4

We want to find f(0)f(0), so we **substitute** x=0x = 0 into our function: f(0)=tan1(0)f(0) = \tan^{-1}(0)

STEP 5

Now, we're asking, "What angle has a tangent of **zero**?" Remember, the tangent of an angle is defined as the ratio of the *opposite side* to the *adjacent side* in a right-angled triangle.

STEP 6

Imagine that angle getting smaller and smaller.
As the angle approaches zero, the opposite side gets tiny, while the adjacent side stays put.
So the ratio gets closer and closer to zero.

STEP 7

Therefore, tan(0)=0\tan(0) = 0.
This means tan1(0)=0\tan^{-1}(0) = 0.
So, f(0)=tan1(0)=0f(0) = \tan^{-1}(0) = 0.

STEP 8

Our **final answer** is 00 radians!

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord