Math

Question Evaluate b2+28b^{2} + 28 when b=2b=2.

Studdy Solution

STEP 1

Assumptions1. The value of bb is. We need to substitute the value of bb into the expression b+28b^{}+28

STEP 2

Substitute the value of bb into the expression.
b2+28=22+28b^{2}+28 =2^{2}+28

STEP 3

Calculate the value of 222^{2}.
22=2^{2} =

STEP 4

Substitute the value of 222^{2} into the expression.
22+28=4+282^{2}+28 =4+28

STEP 5

Calculate the value of 4+284+28.
4+28=324+28 =32The value of the expression b2+28b^{2}+28 when b=2b=2 is32.

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