Math

Question Evaluate 16b+1124\frac{1}{6}b + \frac{11}{24} when b=14b = \frac{1}{4}, and simplify the expression.

Studdy Solution

STEP 1

Assumptions
1. We are given that b=14b=\frac{1}{4}.
2. We need to evaluate the expression 16b+1124\frac{1}{6} b+\frac{11}{24}.
3. We will substitute the value of bb into the expression and simplify.

STEP 2

Substitute the value of bb into the expression.
16b+1124=16(14)+1124\frac{1}{6} b+\frac{11}{24} = \frac{1}{6} \left(\frac{1}{4}\right) + \frac{11}{24}

STEP 3

To simplify the expression, we first multiply 16\frac{1}{6} by 14\frac{1}{4}.
16×14=124\frac{1}{6} \times \frac{1}{4} = \frac{1}{24}

STEP 4

Now we can rewrite the expression with the calculated value.
124+1124\frac{1}{24} + \frac{11}{24}

STEP 5

Since both terms have the same denominator, we can add the numerators directly.
1+1124\frac{1 + 11}{24}

STEP 6

Add the numerators.
1224\frac{12}{24}

STEP 7

Simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 12.
12÷1224÷12\frac{12 \div 12}{24 \div 12}

STEP 8

Calculate the simplified fraction.
12\frac{1}{2}
The evaluated expression 16b+1124\frac{1}{6} b+\frac{11}{24} when b=14b=\frac{1}{4} is 12\frac{1}{2}.

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