Math

QuestionCalculate (2x12)+(12xy10)(2 x-12)+\left(\frac{1}{2} x y-10\right) for x=8x=8 and y=2y=2. Choices: -10, 6, 2, -8.

Studdy Solution

STEP 1

Assumptions1. The expression given is (x12)+(1xy10)( x-12)+\left(\frac{1}{} x y-10\right). The values of the variables are x=8x=8 and y=y=

STEP 2

We need to substitute the given values of xx and yy into the expression. Let's start with the first part of the expression (2x12)(2x -12).
2x12=28122x -12 =2*8 -12

STEP 3

Now, calculate the value of the first part of the expression.
2812=16122*8 -12 =16 -12

STEP 4

implify the value of the first part of the expression.
1612=416 -12 =4

STEP 5

Now, substitute the given values of xx and yy into the second part of the expression (12xy10)\left(\frac{1}{2} x y-10\right).
12xy10=128210\frac{1}{2} x y -10 = \frac{1}{2}*8*2 -10

STEP 6

Calculate the value of the second part of the expression.
128210=810\frac{1}{2}*8*2 -10 =8 -10

STEP 7

implify the value of the second part of the expression.
10=2 -10 = -2

STEP 8

Now that we have the values of both parts of the expression, we can add them together to find the value of the entire expression.
4+(2)=24 + (-2) =2So, the value of the expression (2x12)+(12xy10)(2 x-12)+\left(\frac{1}{2} x y-10\right) for x=8x=8 and y=2y=2 is2.

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